0=-16x^2+x+150

Solution for 0=-16x^2+x+150 equation:

0=-16x^2+x+150

We move all terms to the left:

0-(-16x^2+x+150)=0

We add all the numbers together, and all the variables

-(-16x^2+x+150)=0

We get rid of parentheses

16x^2-x-150=0

We add all the numbers together, and all the variables

16x^2-1x-150=0

a = 16; b = -1; c = -150;
Δ = b2-4ac
Δ = -12-4·16·(-150)
Δ = 9601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{9601}}{2*16}=\frac{1-\sqrt{9601}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{9601}}{2*16}=\frac{1+\sqrt{9601}}{32}
$